20 Quadratic Equations Quiz Questions and Answers

Quadratic equations are polynomial equations of the second degree, typically written in the standard form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants, and \(a \neq 0\).

The solutions can be found using the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 – 4ac}}{2a}\). The discriminant, \(b^2 – 4ac\), determines the nature of the roots: positive for two distinct real roots, zero for one real root, and negative for two complex roots.

Graphically, quadratic equations represent parabolas. If \(a > 0\), the parabola opens upwards; if \(a < 0\), it opens downwards. The vertex, axis of symmetry, and y-intercept provide key insights into the graph's shape and position. Quadratic equations have wide applications in fields like physics (e.g., projectile motion), engineering (e.g., optimization problems), and economics (e.g., maximizing revenue). For instance, solving \(x^2 - 4x + 3 = 0\) yields roots \(x = 1\) and \(x = 3\), which might represent break-even points in a business model.

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Part 2: 20 quadratic equations quiz questions & answers

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Question 1:
Solve the quadratic equation \(x^2 + 5x + 6 = 0\).
A. \(x = -2, -3\)
B. \(x = 2, 3\)
C. \(x = -1, -6\)
D. \(x = 1, 6\)

Answer: A
Explanation: Factoring the equation gives \((x + 2)(x + 3) = 0\), so the roots are \(x = -2\) and \(x = -3\).

Question 2:
Solve \(2x^2 – 3x – 2 = 0\).
A. \(x = 2, -0.5\)
B. \(x = -2, 1\)
C. \(x = 2, 1\)
D. \(x = -1, 2\)

Answer: A
Explanation: Using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 – 4ac}}{2a}\) where a=2, b=-3, c=-2, we get \(x = \frac{3 \pm \sqrt{9 + 16}}{4} = \frac{3 \pm 5}{4}\), so \(x = 2\) or \(x = -0.5\).

Question 3:
Find the roots of \(x^2 – 4x + 4 = 0\).
A. \(x = 2, 2\)
B. \(x = -2, -2\)
C. \(x = 4, 1\)
D. No real roots

Answer: A
Explanation: Factoring gives \((x – 2)^2 = 0\), so the double root is \(x = 2\).

Question 4:
Solve \(3x^2 + 2x – 1 = 0\).
A. \(x = 0.5, -2/3\)
B. \(x = 1, -1\)
C. \(x = 0.33, -1\)
D. \(x = -0.5, 1\)

Answer: A
Explanation: Quadratic formula: \(x = \frac{-2 \pm \sqrt{4 + 12}}{6} = \frac{-2 \pm \sqrt{16}}{6} = \frac{-2 \pm 4}{6}\), so \(x = 0.5\) or \(x = -2/3\).

Question 5:
What are the solutions to \(x^2 + 6x + 9 = 0\)?
A. \(x = -3, -3\)
B. \(x = 3, 3\)
C. \(x = -9, 1\)
D. No solutions

Answer: A
Explanation: Factoring: \((x + 3)^2 = 0\), so \(x = -3\) (repeated root).

Question 6:
Determine the discriminant of \(2x^2 + 4x + 2 = 0\).
A. 0
B. 8
C. -8
D. 4

Answer: A
Explanation: Discriminant = \(b^2 – 4ac = 16 – 16 = 0\), indicating one real root.

Question 7:
For the equation \(x^2 – 5x + 6 = 0\), what is the discriminant?
A. 1
B. 25
C. 1
D. 1

Answer: A
Explanation: Discriminant = \(25 – 24 = 1\), indicating two distinct real roots.

Question 8:
Calculate the discriminant for \(3x^2 – 2x + 1 = 0\).
A. -8
B. 4
C. 8
D. 0

Answer: A
Explanation: Discriminant = \(4 – 12 = -8\), which is negative, so no real roots.

Question 9:
What is the discriminant of \(x^2 + x + 1 = 0\)?
A. -3
B. 1
C. 5
D. 3

Answer: A
Explanation: Discriminant = \(1 – 4 = -3\), indicating complex roots.

Question 10:
For \(4x^2 + 4x + 1 = 0\), find the discriminant.
A. 0
B. 12
C. -12
D. 4

Answer: A
Explanation: Discriminant = \(16 – 16 = 0\), so one real root.

Question 11:
Find the vertex of the parabola \(y = x^2 – 4x + 3\).
A. (2, -1)
B. (-2, 3)
C. (4, 3)
D. (0, 3)

Answer: A
Explanation: Vertex formula: \(x = -\frac{b}{2a} = \frac{4}{2} = 2\), then y = (2)^2 – 4(2) + 3 = -1, so vertex is (2, -1).

Question 12:
What is the vertex of \(y = 2x^2 + 8x + 5\)?
A. (-2, -3)
B. (2, 5)
C. (-4, 5)
D. (0, 5)

Answer: A
Explanation: \(x = -\frac{8}{4} = -2\), then y = 2(-2)^2 + 8(-2) + 5 = -3, so vertex is (-2, -3).

Question 13:
For \(y = -x^2 + 2x – 1\), determine the vertex.
A. (1, 0)
B. (-1, 0)
C. (2, -1)
D. (0, -1)

Answer: A
Explanation: \(x = -\frac{2}{2(-1)} = 1\), then y = -(1)^2 + 2(1) – 1 = 0, so vertex is (1, 0).

Question 14:
Find the vertex of \(y = 3x^2 – 6x + 2\).
A. (1, -1)
B. (2, 2)
C. (-1, 2)
D. (0, 2)

Answer: A
Explanation: \(x = \frac{6}{6} = 1\), then y = 3(1)^2 – 6(1) + 2 = -1, so vertex is (1, -1).

Question 15:
What is the vertex for \(y = x^2 + 2x + 1\)?
A. (-1, 0)
B. (1, 1)
C. (-1, 1)
D. (0, 1)

Answer: A
Explanation: \(x = -\frac{2}{2} = -1\), then y = (-1)^2 + 2(-1) + 1 = 0, so vertex is (-1, 0).

Question 16:
A rectangle has a length 2 more than its width. If the area is 15 square units, what is the width?
A. 3 units
B. 5 units
C. 2 units
D. 4 units

Answer: A
Explanation: Let width = x, then length = x+2. Equation: x(x+2) = 15 → x^2 + 2x – 15 = 0. Solving: x = [-2 ± √(4+60)]/2 = [-2 ± √64]/2 = [-2 + 8]/2 = 3 (positive root).

Question 17:
The sum of two numbers is 10, and their product is 24. What are the numbers?
A. 6 and 4
B. 8 and 2
C. 12 and -2
D. 5 and 5

Answer: A
Explanation: Let numbers be x and y. x + y = 10, xy = 24. Quadratic: t^2 – 10t + 24 = 0 → (t-6)(t-4)=0, so numbers are 6 and 4.

Question 18:
A ball is thrown upwards with initial velocity 20 m/s. When does it reach the ground? (Use h = ut – 0.5gt^2, h=0)
A. 4 seconds
B. 2 seconds
C. 5 seconds
D. 10 seconds

Answer: A
Explanation: 0 = 20t – 0.5(10)t^2 → 5t^2 – 20t = 0 → 5t(t-4)=0, so t=4 seconds (ignoring t=0).

Question 19:
If the profit function is P = -2x^2 + 100x – 500, what production level maximizes profit?
A. 25 units
B. 50 units
C. 100 units
D. 20 units

Answer: A
Explanation: Vertex: x = -b/2a = -100/(2*(-2)) = 25 units.

Question 20:
Two pipes fill a tank in 4 and 6 hours respectively. How long to fill together?
A. 2.4 hours
B. 3 hours
C. 4 hours
D. 2 hours

Answer: A
Explanation: Let t be time. Equation: (1/4 + 1/6)t = 1 → (3/12 + 2/12)t = 1 → (5/12)t = 1 → t = 12/5 = 2.4 hours.

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